We’re being asked to determine the oxidation state of phosphorus in PO 4 3– (phosphate ion).. Since it is a neutral compound its total charge is 0. For an ion (Li +, Al 3+, etc.) = 0. 4 years ago. What are the oxidation numbers of carbon in CO 2, CH4 and C2H6? O.S. B. Hope you get that. General Rules:. We know that oxygen has an oxidation number of -2. C-3 to + 3. Similarly, nitrogen forms nitric acid, HNO 3 , which contains an N=O double bond, whereas phosphorus forms phosphoric acid, H 3 PO 4 , which contains P-O single bonds, as shown in the figure below. The rules for oxidation states are as follows:. 2. B-1 to +1. Anonymous. 2x = 14 - 4 = 10. x = 5. 1 answer. Phosphorous belongs to group 1 5. The problem wants to determine the oxidation number of Phosphorus in the compound. Of the first atoms in each of the following formulas, which one has the highest oxidation number? add the oxidation numbers for each element, using H = +1 and O = -2, let x be the oxidation no for P in this compound. When phosphorus forms an ion with the same oxidation number, it is the phosphate, PO 4 3-, ion, as shown in the figure below. The oxidation number of phosphorus vary from: A-3 to +5. The oxidation state of vanadium in Rb4NaHV10O28 is: A) -6 B) +8 C) -5 D) +3 E) +5 Q. What is the oxidation no. MEDIUM. D-5 to +1. As this compound is neutral, then it is true that the sum of all the charges present is 0: A) CO3 2- B) NO3- C) SO3 D) ClO3- E) P2O5 Q. Access a diverse Question Bank and ask You Own Doubt Now For an atom in its elemental form (Zn, Cl 2, C (graphite), etc.) It has 5 electrons in its valence shell. Let oxidation number of P be x So 2(x)+5(-2)=0 2x=10 x=5 Thus oxidation number of phosphorous is +5. Suppose that the oxidation number of phosphorus is {eq}x {/eq}. 1. common oxidation no.-3 : Maximum oxidation number : 5 : Max. The answer to this question is: 3 is the oxidation state of phosphorus in PF3.. Vist BYJU'S for a detailed answer to this question. A. +3 Phophite (PO_3^(3-)) has a charge of -3, so I'm going to guess you meant to ask what the oxidation state of P was in H_3PO_3 In H_3PO_3 the oxygens will always have a -2 charge and hydrogen is +1. The sum of oxidation numbers should equal the ionic charge (-2) +2 + 2x -7*2 = -2. 3 0. The ion {eq}PO_4^{3-} {/eq} has 1 Phosphorus atom and 4 Oxygen atoms. The ion has a -3 charge. O.S. common oxidation no. Oxidation Number Of P. Minimum oxidation number-3 : Min. Oxidation number of phosphorus ← Prev Question Next Question → Related questions 0 votes. Specific Rules: = charge. Answer. 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